To determine the displacement of the car during the given time, we need to convert the speed from km/h to m/s, as the unit of acceleration also needs to be in m/s².
1 km/h is equivalent to 1000 m / 3600 s = 5/18 m/s.
The final speed of the car is 23.7 km/h, which is equal to (23.7 * 5/18) m/s = 6.583 m/s (rounded to three decimal places).
The initial speed of the car is 0 m/s since it started from rest.
The time taken is 6.5 s.
To find the displacement, we can use the equation:
s = ut + (1/2)at^2
where:
s = displacement
u = initial velocity
t = time
a = acceleration
Since the acceleration is uniform, we can assume a = (v - u) / t, where v is the final velocity.
Thus, a = (6.583 m/s - 0 m/s) / 6.5 s = 1.012 m/s² (rounded to three decimal places).
Plugging the values into the equation:
s = 0 * 6.5 + (1/2) * 1.012 * (6.5)^2
s = 0 + 0.5 * 1.012 * 42.25
s = 21.38325 m (rounded to five decimal places)
Therefore, the car travels approximately 21.38325 meters during the given time of 6.5 seconds.