To calculate the amount of sulfuric acid (H2SO4) that can be prepared from 29 moles of sulfur, we need to determine the stoichiometry of the reaction and the molar mass of sulfuric acid.
The balanced chemical equation for the conversion of sulfur (S) to sulfuric acid (H2SO4) is as follows:
S + O2 → SO2
2 SO2 + O2 → 2 SO3
SO3 + H2O → H2SO4
From the balanced equations, we can see that 1 mole of sulfur (S) reacts to produce 1 mole of sulfur dioxide (SO2), and subsequently, 1 mole of sulfur dioxide reacts to produce 1 mole of sulfur trioxide (SO3). Finally, 1 mole of sulfur trioxide reacts with water (H2O) to produce 1 mole of sulfuric acid (H2SO4).
Therefore, the amount of sulfuric acid that can be prepared from 29 moles of sulfur is also 29 moles.
To convert moles to grams, we need to multiply the number of moles by the molar mass of sulfuric acid (98.09 g/mol).
So, 29 moles of sulfuric acid is equal to:
29 moles x 98.09 g/mol = 2,843.61 g
Therefore, 29 moles of sulfur can be converted to 2,843.61 grams of sulfuric acid.