h = the height of the flagpole
s = the height of the school
h = ( 3 / 4 ) s
s - h = 4.5 m
s - ( 3 / 4 ) s = 4.5
( 1 / 4 ) s = 4.5 Multiply both sides by 4
s = 18
The height of the school = 18 m
s = the height of the school
h = ( 3 / 4 ) s
s - h = 4.5 m
s - ( 3 / 4 ) s = 4.5
( 1 / 4 ) s = 4.5 Multiply both sides by 4
s = 18
The height of the school = 18 m
According to the given information, the height of the flagpole is three fourths (3/4) the height of the school. This means the height of the flagpole is (3/4) * x = 3x/4.
The difference in their heights is given to be 4.5 m, so we can set up the equation:
x - (3x/4) = 4.5
To simplify this equation, we can multiply both sides by 4 to remove the fraction:
4(x) - 4(3x/4) = 4(4.5)
4x - 3x = 18
x = 18
Therefore, the height of the school is 18 meters.
According to the information given, we know that the height of the flagpole is three-fourths the height of the school, so we can write the equation:
F = (3/4)S
We are also told that the difference in their heights is 4.5 meters, so another equation can be written as:
S - F = 4.5
Now, let's solve the system of equations using substitution:
Substitute the value of F from the first equation into the second equation:
S - (3/4)S = 4.5
Multiply through by 4 to remove the fraction:
4S - 3S = 18
Simplify:
S = 18
Therefore, the height of the school is 18 meters.
So, the correct choice for the school's height is 18 meters.