An energy of 6.0×10−2 J is stored in the metal sphere on top of a Van de Graaff generator. A spark carrying 1.0 micro-coulomb (1.0×10−6 C) discharges the sphere.Find the sphere's potential relative to ground.

Question

An energy of 6.0×10−2 J is stored in the metal sphere on top of a Van de Graaff generator. A spark carrying 1.0 micro-coulomb (1.0×10−6 C) discharges the sphere.Find the sphere's potential relative to ground.

last one for the night

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4 answers
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Answer 1

drwls answered
12 years ago

Energy = Q*V

V = Energy/Q = 6*10^-2/10^-6 = 60,000 V

Answer 2

Clown Bot answered
9 months ago

Well, well, well, looks like someone's trying to zap me with a tricky question before bedtime! Alright, challenge accepted!

To find the sphere's potential relative to ground, we can use the formula for electric potential energy (U) given by U = qV, where q is the charge and V is the potential. In this case, the charge is 1.0×10^(-6) C and the energy is 6.0×10^(-2) J.

Rearranging the formula, we get V = U/q. Plugging in the values, we have V = (6.0×10^(-2) J) / (1.0×10^(-6) C).

Calculating this, we get V ≈ 60,000 V.

So, the potential of that metal sphere relative to ground is approximately 60,000 volts! That's electrifying! Sleep tight!

Answer 3

Step-by-Step Bot answered
8 months ago

To find the potential of the sphere relative to ground, we can use the formula:

Potential = Energy / Charge

Given:
Energy = 6.0 × 10^-2 J
Charge = 1.0 × 10^-6 C

Substituting the values into the formula, we get:

Potential = (6.0 × 10^-2 J) / (1.0 × 10^-6 C)

Simplifying the expression, we have:

Potential = 6.0 × 10^4 J/C

Therefore, the sphere's potential relative to ground is 6.0 × 10^4 J/C.

Answer 4

Explain Bot answered
8 months ago

To find the sphere's potential relative to ground, we can make use of the formula that relates energy and electric potential. The formula is:

E = Q * V

Where:
- E is the energy stored in the metal sphere (6.0×10^(-2) J).
- Q is the charge that discharges through the sphere (1.0×10^(-6) C).
- V is the potential difference or electric potential we are trying to find.

Rearranging the formula, we get:

V = E / Q

Substituting the given values, we have:

V = 6.0×10^(-2) J / 1.0×10^(-6) C

To simplify this expression, divide 6.0 by 1.0, which equals 6.0:

V = 6.0 × 10^(-2-(-6))

Next, we subtract the exponents: -2 - (-6) = -2 + 6 = 4:

V = 6.0 × 10^4

Therefore, the sphere's potential relative to ground is 6.0 × 10^4 volts.