Hemoglobin, an oxygen-carrying protein in blood, contains 4 iron atoms per molecule and the iron comprises 0.34% of the molecules mass. What is the molecular weight of hemoglobin?
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4*atomic mass Fe/molar mass hemoglobin = 0.0034
Solve for molar mass hemoglobin.
A.t.q
Mol3cular weight= 56×4/0.34×100
To find the molecular weight of hemoglobin, we need to consider the atomic weights of all the elements present and multiply them by their respective number of atoms in a hemoglobin molecule.
First, let's find the atomic weight of iron (Fe) using the periodic table. The atomic weight of iron is approximately 55.85 g/mol.
Next, let's calculate the mass of the iron atoms in hemoglobin. We are given that iron makes up 0.34% of the molecule's mass. This means that 0.34% of the molecular weight is due to the iron.
To calculate the molecular weight, we divide the percentage of iron by its atomic weight and multiply by 100 to convert it into grams.
0.34% of the molecular weight = (0.34/100) * (4 atoms of iron) * (55.85 g/mol) = 0.612 g/mol.
Next, let's calculate the percentage of the molecular weight that is not due to iron. We can do this by subtracting the percentage of iron from 100%.
Percentage without iron = 100% - 0.34% = 99.66%.
Now, let's calculate the molecular weight of hemoglobin without the iron portion. To do this, we need to divide the percentage without iron by 100 and then divide the remaining mass by the mass without iron.
Molecular weight without iron = (100/99.66) * (0.612 g/mol) = 0.615 g/mol.
Finally, let's calculate the total molecular weight of hemoglobin. Since there are 4 iron atoms per molecule, we need to multiply the molecular weight without iron by 4 and add the mass due to the iron atoms.
Total molecular weight of hemoglobin = (4 * 0.615 g/mol) + 0.612 g/mol = 2.48 g/mol + 0.612 g/mol = 3.092 g/mol.
Therefore, the molecular weight of hemoglobin is approximately 3.092 g/mol.