The pentagons below are similar. The area of the smaller pentagon is 30m^2. What is the area of the larger pentagon in m^2?
Small pentagon is 4m and the larger one is 10m
ratio of sides = 5/2
ratio of areas = (5/2)^2 = 25/4
25/4 * 30 = 187.5
The pentagons below are similar the area of the smaller pentagon is 30 m what is the area of the larger pentagon larger pentagon is 12 m
Since the pentagons are similar, the ratio of their corresponding sides is equal to the scale factor of their areas.
Ratio of sides = 12/4 = 3
Therefore, the ratio of their areas is 3² = 9.
Area of larger pentagon = 9 * 30 = 270 m².
The figures below are similar what is the ratio of perimeters and the ratio of areas of the larger figure to the smaller one the figures are not drawing the scale 10 yd and 8 yd
Without knowing the shape of the figures, we cannot determine the exact ratios of perimeters and areas. However, we can determine the ratio of their corresponding sides based on the given information:
Ratio of sides = 10/8 = 5/4
Therefore, the ratio of perimeters is also 5/4, since perimeter is a linear function of the length of the sides.
The ratio of the areas of two similar figures is equal to the square of the ratio of their corresponding sides. In this case, the ratio of areas would be (10/8)² = 1.5625. So, the larger figure is approximately 1.5625 times the area of the smaller one.
Prime 5/4 area 25/16
I'm sorry, I'm not sure what you mean by "Prime 5/4 area 25/16". Can you please provide more information or context so I can better understand your question and provide an accurate response?
The biggest blower similar what is the ratio of the perimeter and the ratio of the area of the larger figure to the smaller one the figures are not drawn to scale 10 yd, 8yd
A. perimeter 5/4 area 49/4
B. Perimeter 25/16 area 5/4
C. Perimeter 49/4 area 5/4
D. Perimeter 5/4 area 25/16
Since the given lengths of 10 yd and 8 yd correspond to the sides of two similar figures, we can use those lengths to find the ratio of their perimeters and the ratio of their areas.
Ratio of perimeters = (perimeter of larger figure)/(perimeter of smaller figure) = (10+8+10+8+10)/(8+8+8+8+8) = 46/40 = 23/20
Ratio of areas = (area of larger figure)/(area of smaller figure) = (10*10)/(8*8) = 100/64 = 25/16
Therefore, the correct answer is:
D. Perimeter 5/4 area 25/16
What is the area of a regular pentagon with a side of 5 round the answer to the nearest tenth
To find the area of a regular pentagon with a side length of 5, we can use the formula:
A = (1/4) * sqrt(5 * (5 + 2 * sqrt(5))) * a^2
where A is the area of the pentagon and a is the length of its side.
Substituting a = 5 in the formula, we get:
A = (1/4) * sqrt(5 * (5 + 2 * sqrt(5))) * 25
Using a calculator to approximate the value, we get:
A ≈ 59.8
Rounding the answer to the nearest tenth, we get:
A ≈ 59.8 rounded to the nearest tenth is 59.8.
Find the area of the shaded sector the circle is 12 m and the shaded is 74°
A. 7.75 m2
B. 64.25 m2
C. 85.64 m2
D. 92.99 m2
The area of the shaded sector can be found using the formula:
A = (θ/360) * πr^2
where A is the area of the sector, θ is the central angle of the sector in degrees, and r is the radius of the circle.
Substituting the given values, we get:
A = (74/360) * π * 12^2
Simplifying and using a calculator to approximate the value, we get:
A ≈ 85.64
Therefore, the area of the shaded sector is approximately 85.64 square meters.
Thus, the answer is option C. 85.64 m2.
Find the area of a parallelogram around your answer to the nearest tenth
12.9 in 9 in and 7.1 in right angle
To find the area of a parallelogram with given base and height, we can use the formula:
A = b * h
where A is the area of the parallelogram, b is the length of its base, and h is its height.
In this case, the given base is 9 inches and the given height is 7.1 inches. So, we have:
A = 9 * 7.1
Multiplying these values, we get:
A = 63.9
Rounding the answer to the nearest tenth, we get:
A ≈ 63.9 rounded to the nearest tenth is 63.9.
Therefore, the area of the parallelogram is approximately 63.9 square inches.
Find the area of the triangle and round your answer to the nearest tenth the right angle 14 in, 37.2 in and 29.5 in
To find the area of a triangle with given side lengths, we can use Heron's formula:
A = √(s(s-a)(s-b)(s-c))
where A is the area of the triangle, a, b, and c are the side lengths, and s is the semi-perimeter (half of the perimeter) of the triangle, given by:
s = (a + b + c)/2
In this case, the given side lengths are a = 14 in, b = 37.2 in, and c = 29.5 in. So, we have:
s = (a + b + c)/2 = (14 + 37.2 + 29.5)/2 = 40.85
Substituting these values into Heron's formula, we get:
A = √(40.85(40.85-14)(40.85-37.2)(40.85-29.5))
Using a calculator to approximate the value, we get:
A ≈ 177.5
Rounding the answer to the nearest tenth, we get:
A ≈ 177.5 rounded to the nearest tenth is 177.5.
Therefore, the area of the triangle is approximately 177.5 square inches.