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P1V1 = P2V2
0.60*27 = P2*3.0
P2 = 0.60*27/3.0 = 5.4 atm.
A gas under an initial pressure of 0.60atm is compressed at a constant temperature from 27L to 3.0L. The final pressure will become? (5.4atm) (how did she get this answer?)
0.60*27 = P2*3.0
P2 = 0.60*27/3.0 = 5.4 atm.