To determine how many grams of PbCO3 will dissolve when 1.0 L of 1.00 M H+ is added to 6.00 g of PbCO3, we need to follow these steps:
Step 1: Calculate the number of moles of H+ present in 1.0 L of 1.00 M H+ solution.
First, we need to calculate the number of moles of H+ in the solution. The concentration is given as 1.00 M, which means there is 1 mole of H+ per liter of solution. Therefore, 1.0 L of 1.00 M H+ solution contains 1.00 moles of H+.
Step 2: Calculate the molar mass of PbCO3.
To calculate the molar mass of PbCO3, we need to determine the atomic masses of each element in the compound.
The atomic masses are:
Pb: 207.2 g/mol
C: 12.01 g/mol
O: 16.00 g/mol
The molar mass of PbCO3 is calculated as follows:
Molar mass of PbCO3 = (207.2 g/mol) + (12.01 g/mol) + (3 × 16.00 g/mol)
= 207.2 g/mol + 12.01 g/mol + 48.00 g/mol
= 267.21 g/mol
Step 3: Convert the given mass of PbCO3 (6.00 g) to moles.
To convert grams to moles, we divide the given mass (in grams) by the molar mass (in grams/mol).
Number of moles of PbCO3 = 6.00 g / 267.21 g/mol
= 0.0225 mol
Step 4: Determine the limiting reactant.
To determine the limiting reactant, we compare the stoichiometric ratio between PbCO3 and H+ in the balanced equation.
From the equation, we can see that two moles of H+ are required to react with one mole of PbCO3. Therefore, the stoichiometric ratio is 2:1.
Since we have 1.00 mole of H+ and 0.0225 moles of PbCO3, we can conclude that PbCO3 is the limiting reactant because it is in smaller quantity.
Step 5: Calculate the moles of PbCO3 that will react.
Since PbCO3 is the limiting reactant, all of it will react with the H+ ions.
Therefore, the moles of PbCO3 that will react are equal to the initial moles of PbCO3, which is 0.0225 mol.
Step 6: Convert moles of PbCO3 to grams.
To convert moles of PbCO3 to grams, we multiply the moles by the molar mass of PbCO3.
Mass of PbCO3 that will react = 0.0225 mol × 267.21 g/mol
= 6.01 g (rounded to two decimal places)
Therefore, when exactly 1.0 L of 1.00 M H+ is added to 6.00 g of PbCO3, approximately 6.01 grams of PbCO3 will dissolve.