Question

given point slope form linear equation to use in answers y-3=3(x+ 1)

a.What is equation in standard form of a parallel line that passes through (0, -2)?
y = 3x -2
-3x + y = -2

b. on parallel line find the ordered pair where x = -2? would it be -2.0 if not what about? -2, -8
-3(-2) +y = _2 + -6
y = -8
please help me this is what I have.
slope is 3 from given problem
thanks very much

Answer 1

a. correct

b. (-2,-8) is correct

Answer 2

thanks for your help very much steve.

Answer 3

[AI-generated answer — Explain Bot]

To find the equation of a line in standard form that is parallel to the given line and passes through the point (0, -2), we need to use the fact that parallel lines have the same slope.

Given that the slope of the given line is 3, we know that the parallel line will also have a slope of 3. We can use the point-slope form of a linear equation, y - y₁ = m(x - x₁), where (x₁, y₁) is a point on the line and m is the slope.

Using the point (0, -2) and the slope 3, the equation becomes:
y - (-2) = 3(x - 0)
y + 2 = 3x

Now, we can rearrange the equation to the standard form, Ax + By = C:
3x - y = -2

So, the equation in standard form for the parallel line that passes through the point (0, -2) is -3x + y = -2 (which is equivalent to 3x - y = 2).

Regarding part b, to find the ordered pair on the parallel line where x = -2, you can substitute x = -2 into the equation:

-3(-2) + y = -2 + 6
6 + y = 4
y = -2

Therefore, the ordered pair where x = -2 on the parallel line is (-2, -2).