Hard water contains Ca ,Mg ,Fe and , which interfere with the action of soap and leave an insoluble coating on the insides of containers and pipes when heated. Water softeners replace these ions with Na.

If 1100. of hard water contains 0.021 M of Ca and 0.0060 M of Mg , how many moles of Na are needed to replace these ions?

If the sodium is added to the water softener in the form of , how many grams of sodium chloride are needed?

How many moles Ca and Mg do you have? That will be M x L = 1100 x 0.021 = ? moles Ca and

1100 x 0.0060 = ?moles Mg.
Total moles Ca+Mg = the sum.

Since the valence of Ca and Mg is two and that of Na is one, it will take twice as many moles of Na as you have for the sum of Mg + Ca.
You didn't answer the second part of my first response but I assume you meant how many grams of NaCl are needed.
So you have total moles Na needed, so moles = grams/molar mass. Substitute moles Na and molar mass NaCl to find grams NaCl.

Hard water contains Ca ,Mg ,Fe and , which interfere with the action of soap and leave an insoluble coating on the insides of containers and pipes when heated. Water softeners replace these ions with Na.

If 1100. L of hard water contains 0.021 M of Ca and 0.0060 M of Mg , how many moles of Na are needed to replace these ions?

If the sodium is added to the water softener in the form of , how many grams of sodium chloride are needed?

If 1500. of hard water contains 0.019 and 0.0070 , how many moles of are needed to replace these ions?

If the sodium is added to the water softener in the form of NaCl , how many grams of sodium chloride are needed?

nose jaja saludos

Oh, sodium to the rescue! Let's crunch those numbers and figure out how many moles of Na are needed.

We know that 1100. mL of hard water contains 0.021 M of Ca and 0.0060 M of Mg. Since we want to replace both ions, we'll need to double the moles of each. So, 0.021 M of Ca becomes 2 * 0.021 = 0.042 moles of Ca, and 0.0060 M of Mg becomes 2 * 0.0060 = 0.012 moles of Mg.

Since water softeners replace these ions with Na, we need an equal number of moles of Na. Therefore, we need 0.042 moles of Na to replace the Ca, and 0.012 moles of Na to replace the Mg. Adding these up, we find that we need a total of 0.042 + 0.012 = 0.054 moles of Na.

Now, let's move on to the second part of the question and find out how many grams of sodium chloride (NaCl) we need.

Since 1 mole of NaCl is made up of 1 mole of Na and 1 mole of Cl, we can say that 1 mole of NaCl is needed for every 1 mole of Na. So, we need 0.054 moles of NaCl to supply the required 0.054 moles of Na.

To convert moles to grams, we need to know the molar mass of NaCl, which is 58.44 g/mol. Multiplying the molar mass by the number of moles, we find that we need 0.054 * 58.44 = 3.157 grams of sodium chloride.

So, to replace the calcium and magnesium ions in 1100. mL of hard water, we need approximately 0.054 moles of Na and 3.157 grams of sodium chloride. Time for some softening magic!

To figure out how many moles of Na are needed to replace the Ca and Mg ions in the hard water, we need to determine the number of moles of Ca and Mg ions present and then calculate the equivalent amount of Na ions required.

1. Calculate moles of Ca:
Moles of Ca = concentration of Ca ions x volume of hard water
= 0.021 M x 0.1100 L
= 0.00231 moles

2. Calculate moles of Mg:
Moles of Mg = concentration of Mg ions x volume of hard water
= 0.0060 M x 0.1100 L
= 0.00066 moles

3. Calculate moles of Na required:
Moles of Na = sum of moles of Ca and Mg
= 0.00231 moles + 0.00066 moles
= 0.00297 moles

Therefore, 0.00297 moles of Na are needed to replace the Ca and Mg ions.

To calculate how many grams of sodium chloride (NaCl) are needed, we need to consider the molar mass of NaCl and convert moles to grams.

4. Determine the molar mass of NaCl:
The molar mass of NaCl is calculated by adding the atomic masses of sodium (Na) and chlorine (Cl).
Molar mass of Na = 22.99 g/mol
Molar mass of Cl = 35.45 g/mol
Molar mass of NaCl = 22.99 g/mol + 35.45 g/mol
= 58.44 g/mol

5. Calculate grams of NaCl required:
Grams of NaCl = moles of NaCl x molar mass of NaCl
= 0.00297 moles x 58.44 g/mol
= 0.1736 grams

Therefore, approximately 0.1736 grams of sodium chloride (NaCl) are needed to replace the Ca and Mg ions in the hard water.

1100 WHAT of hard water?

If the sodium is .........in the form of WHAT, how many........needed?