4al+3o2 2al2o3 what volume of o2 do you need to use up 100kg Al at SATP
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To calculate the volume of O2 required to use up 100kg of Al at SATP (Standard Ambient Temperature and Pressure), we need to use the molar ratios of Al to O2 from the balanced equation.
The balanced equation is: 4Al + 3O2 -> 2Al2O3
Step 1: Convert mass of Al to moles:
The molar mass of Al is 26.98 g/mol, so we can calculate the number of moles of Al in 100kg (100,000g) using the formula:
moles of Al = mass of Al / molar mass of Al
moles of Al = 100,000g / 26.98g/mol
Step 2: Use the molar ratio of Al to O2 from the balanced equation:
From the balanced equation, we know that 4 moles of Al react with 3 moles of O2.
3 moles of O2 react with 4 moles of Al
So, moles of O2 = (moles of Al) × (3/4)
Step 3: Use the ideal gas law to calculate the volume of O2:
The ideal gas law is given by: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.
At SATP, the pressure (P) is 1 atm, the temperature (T) is 273.15K, and the ideal gas constant (R) is 0.0821 L·atm/(mol·K).
Rearrange the ideal gas law to solve for volume (V):
V = (nRT) / P
Substitute the value of n (from Step 2), R, P, and T into the equation and solve for V.
Finally, the calculated volume of O2 will represent the volume of O2 in liters required to use up 100kg of Al at SATP.