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CH3NH2 + HOH --> CH3NH3^+ + OH^-
Kb = (CH3NH3^+)(OH^-)/(CH3NH2)
Make an ICE chart and substitute into the Kb expression I've written.
(CH3NH2) = 0.175 x (65/225) = ?
(CH3NH3^+) = x
(OH^-) = x
Solve for x, convert OH^- to pH.