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How many grams of ice are needed to cool 250 ml of water from 75 degrees celcius to 5 degrees celcius?

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  1. Note the correct spelling of celsius.
    Heat gained by ice + heat gained by melted water + heat lost by original water = 0

    [mass ice x heat fusion] + [mass melted ice x specific water x (Tfinal-Tinitial)] + [mass 250mL water x specific heat water x (Tfinal-Tinitial)] = 0
    Solve for mass ice (and melted ice). I think something like 200 g ice is necessary but that is an aproximation.

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