force = mass x gravity
Force = density x volume x gravity
= 1000 x 4 x 6 x 0.04 x 9.8
= 9408 N
1. Object 1 and 2 have same volume and shape, but object 1 is more dense than object 2, which one has greater buoyant force??
2. object 1 and 2 has same mass, but density of object 1 is greater than object 2(has more volume), which one has the greatest buoyant force?
The greater the volume, the greater the bouyant force. Buoyant force is related to the volume of the fluid displaced.
A ferry boat is 4.0 m wide and 6.0 m long. When a truck pulls onto it, the boat sinks 4.00 cm in the water. What is the combined weight of the truck and the ferry?
Force = density x volume x gravity
= 1000 x 4 x 6 x 0.04 x 9.8
= 9408 N
Force = density x volume x gravity
= 1000 x 4 x 6 x 0.04 x 9.8
= 9408 N
1. We can start by calculating the volume of water displaced by the boat when the truck pulls onto it. The volume of water displaced is equal to the product of the change in height and the base area of the boat.
Volume of water displaced = change in height * width * length
2. Next, we can determine the weight of the water displaced by the boat using the density of water. The weight of the water displaced is equal to the product of the volume of water displaced and the density of water.
Weight of water displaced = volume of water displaced * density of water
3. Since the buoyant force acting on the boat is equal to the weight of the water displaced, we can equate the weight of water displaced to the combined weight of the truck and the ferry.
Combined weight of truck and ferry = weight of water displaced
By following these steps, we can determine the combined weight of the truck and the ferry.
The buoyant force is equal to the weight of the fluid displaced by the boat. In this case, the boat sinks into the water, indicating that it displaces a certain volume of water.
First, let's calculate the volume of water displaced by the boat. The volume of the water displaced is equal to the area of the boat's base multiplied by the depth to which it sinks.
The area of the boat's base is given by the width multiplied by the length: 4.0 m * 6.0 m = 24.0 m^2.
The depth to which the boat sinks is given as 4.00 cm, or 0.04 m.
Therefore, the volume of water displaced by the boat is 24.0 m^2 * 0.04 m = 0.96 m^3.
Next, the buoyant force acting on the boat can be calculated using Archimedes' principle, which states that the buoyant force is equal to the weight of the fluid displaced by the object.
The density of water is approximately 1000 kg/m^3.
So, the weight of the water displaced by the boat is equal to the volume of water displaced multiplied by the density of water: 0.96 m^3 * 1000 kg/m^3 = 960 kg.
Therefore, the combined weight of the truck and the ferry is 960 kg.