Question

What mass of sucrose, C12H22O11, is needed to make 500mL of a 0.20M solution?

Help please...

Thanks.

Answer 1

mass= molmasssucrose*molarity*volumeinliters.

Answer 2

You want 0.2 M.

M = mols/L or mols = L x M = 0.5 x 0.2 = ?? mols sucrose.
mols = grams sucrose/molar mass sucrose
Solve for grams.

Answer 3

[AI-generated answer — Step-by-Step Bot]

To calculate the mass of sucrose needed to make a 0.20M solution in 500mL, you need to use the formula:

m = n x M

Where:
m = mass of sucrose (in grams)
n = amount of substance (in moles)
M = molar mass of sucrose (in g/mol)

First, calculate the amount of substance (moles) using the formula:

n = M x V

where:
M = molarity of the solution (in mol/L or M)
V = volume of the solution (in L)

Given:
M = 0.20M
V = 500mL = 0.5 L

Substitute the values into the formula:

n = 0.20M x 0.5L
= 0.10 mol

Now, calculate the molar mass of sucrose:

M = (12.01 g/mol x 12) + (1.01 g/mol x 22) + (16.00 g/mol x 11)
= 342.34 g/mol

Finally, substitute the values into the formula for mass:

m = n x M
= 0.10 mol x 342.34 g/mol
= 34.23 grams

Therefore, you will need approximately 34.23 grams of sucrose to make a 0.20M solution in 500mL.

Answer 4

[AI-generated answer — Explain Bot]

In order to find the mass of sucrose needed to make the solution, we need to use the formula:

Molarity (M) = moles/volume (L)

First, let's convert the volume from milliliters (mL) to liters (L). Since 1 L = 1000 mL, the volume is 500 mL ÷ 1000 mL/L = 0.5 L.

Now, we can rearrange the formula and solve for moles:

moles = Molarity × volume (in L)

Given the molarity (0.20 M) and the volume (0.5 L), we can calculate moles:

moles = 0.20 M × 0.5 L = 0.1 moles

To find the mass of sucrose, we need to know the molar mass of sucrose. By adding up the atomic masses of each element in the chemical formula C12H22O11, we get:

12(12.01 g/mol) + 22(1.01 g/mol) + 11(16.00 g/mol) = 342.34 g/mol

So, the molar mass of sucrose is 342.34 g/mol.

Finally, to find the mass of sucrose needed, we can use the formula:

mass (g) = moles × molar mass (g/mol)

mass = 0.1 moles × 342.34 g/mol = 34.23 g

Therefore, to make a 0.20M solution in 500 mL, you would need 34.23 grams of sucrose (C12H22O11).