Question

An electrical circuit switches instantaneously from a 2 volt battery to a 20 volt battery 3 seconds after being turned on. Sketch on a sheet of paper a graph the battery voltage against time. Then fill in the formulas below for the function represented by your graph.

For t < _____ , V(t) = _____
For t ¡Ý _____, V(t) = _____

At what point or points is your function discontinuous?
t = ______

Answer 1

The change occurred at t=3 seconds.

So at t<3 seconds, V(t)=2 volts
at t>3 seconds, V(t)=? volts

Discontinuity is at t=?

Answer 2

t < 8 V(t) =5

T>8 V(t) =18
t=8

Answer 3

if two resistors with resistances r1 and r2 ohms are connected in parallel in an electric circuit to make an r-ohms resistor , the value of r can be found from the equation 1/r=1/r1+1/r2. if r1 is decreasing at the rate of 1 ohm/sec , and r2 is increasing at the rate of 0.5 ohm/sec , at what rate is r changing when r1=75 ohms and r2=50 ohms

Answer 4

An electrical circuit switches instantaneously from a 3 volt battery to a 23 volt battery 7 seconds after being turned on. Sketch on a sheet of paper a graph the battery voltage against time. Then fill in the formulas below for the function represented by your graph.

Answer 5

jnbkjn

Answer 6

[AI-generated answer — Clown Bot]

Oh boy, I'm no artist, but I'll do my best to sketch this for you. Let's call the time when the circuit turns on, t = 0.

For t < 3 seconds, V(t) = 2 volts (from the 2 volt battery).
For t ≥ 3 seconds, V(t) = 20 volts (after switching to the 20 volt battery).

So, now let's recap:

For t < 3, V(t) = 2.
For t ≥ 3, V(t) = 20.

Hmm, as for the discontinuity, it occurs at t = 3 seconds, where the battery voltage suddenly jumps from 2 volts to 20 volts. It's like the circuit got a shock of energy! Yikes!

I hope that helps! Let me know if you have any more shocking questions!

Answer 7

[AI-generated answer — Explain Bot]

To sketch the graph of the battery voltage against time, let's consider the information given.

Initially, the circuit is connected to a 2 volt battery. Hence, for t < 3 seconds, the voltage remains constant at 2 volts.

Next, at t = 3 seconds, the circuit switches instantaneously to a 20 volt battery. From this point onward (t ≥ 3 seconds), the voltage remains constant at 20 volts.

Therefore, the graph can be sketched as follows:

___________________________
| |
| |
| |
| xxxxxxxxxxx|
| xxxxxx |
| xxxxx |
| xxxx |
| |3s |

Now, let's fill in the formulas for the function represented by the graph:

For t < 3 seconds, V(t) = 2 volts.

For t ≥ 3 seconds, V(t) = 20 volts.

The function is discontinuous at t = 3 seconds because there is an abrupt change in voltage at this point.