(1/3) h * 771^2/vr = (1/3)(486)(594,441)/35*20*8
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Step 1: Calculate the volume of the Great Pyramid of Cheops
The formula for the volume of a pyramid is V = (1/3) * base area * height. In this case, the base area is the area of a square, calculated as side^2.
V_pyramid = (1/3) * side^2 * height
V_pyramid = (1/3) * 771 ft * 771 ft * 486 ft
Step 2: Calculate the volume of each room
The volume of each room is given as 35 ft x 20 ft x 8 ft.
V_room = length * width * height
V_room = 35 ft * 20 ft * 8 ft
Step 3: Calculate the number of rooms needed
To find the number of rooms needed, we divide the volume of the pyramid by the volume of each room.
Number of rooms = V_pyramid / V_room
Now, let's go ahead and calculate the results.
V_pyramid = (1/3) * 771 ft * 771 ft * 486 ft
V_pyramid ≈ 91,764,102 ft^3
V_room = 35 ft * 20 ft * 8 ft
V_room = 5,600 ft^3
Number of rooms ≈ V_pyramid / V_room
Number of rooms ≈ 91,764,102 ft^3 / 5,600 ft^3
Therefore, you would need approximately 16,355 rooms (rounded to the nearest whole number) of dimensions 35 ft x 20 ft x 8 ft in order to have a volume equivalent to that of the Great Pyramid of Cheops.