Vf^2=Vi^2+2ad
0=39^2+2(NetForce/mass)*1270
solve for net force.
note that masscar= 8036/g
8036 N opens at the end of a quarter-mile
run when the car is traveling 39 m/s.
The acceleration of gravity is 9.81 m/s2 .
What net retarding force must be supplied
by the parachute to stop the car in a distance of 1270 m?
Answer in units of N.
0=39^2+2(NetForce/mass)*1270
solve for net force.
note that masscar= 8036/g
First, let's find the mass of the car. We know that weight (W) is equal to mass (m) multiplied by the acceleration due to gravity (g), which is 9.81 m/s^2.
Given: Weight (W) = 8036 N
Acceleration due to gravity (g) = 9.81 m/s^2
Using the formula: W = m * g, we can solve for m:
8036 N = m * 9.81 m/s^2
Divide both sides by 9.81 m/s^2:
8036 N / 9.81 m/s^2 = m
819.4 kg = m
Now that we have the mass of the car, we can proceed to calculate the net retarding force.
The net retarding force can be calculated using Newton's second law:
Force (F) = mass (m) * acceleration (a)
Given: Final velocity (vf) = 0 m/s (as the car needs to stop)
Initial velocity (vi) = 39 m/s
Distance (d) = 1270 m
The acceleration can be calculated using the equation:
vf^2 = vi^2 + 2a * d
Rearranging the equation to solve for acceleration:
a = (vf^2 - vi^2) / (2 * d)
Substituting the given values:
a = (0^2 - 39^2) / (2 * 1270) = (-1521) / 2540 ≈ -0.598 m/s^2
Note: The negative sign indicates that the acceleration is in the opposite direction to the car's initial motion.
Finally, we can calculate the net retarding force using Newton's second law:
F = m * a
Substituting the values:
F = 819.4 kg * (-0.598 m/s^2) ≈ -489.7 N
The net retarding force required to stop the car using the parachute is approximately 489.7 N (in the opposite direction of the car's motion).