9. consider the function y=e^-x sin x where pie < x < pie

find dy/dx which is e^-x(cos x - sin x)

show that at stationary points, tan x = 1. - I have done this part

I don't understand this part:
How do I do this: determine the co-ordinates of the stationary points correct to 2 dp.

Could you tell me how to start off this question?

Reiny Reiny answered
13 years ago

You have show that the condition for stationary points is that tanx = 1

In the next part we actually have to find those points,
that is, solve
tanx = 1
x = 45° or x = 225°
or
x = π/4 or x = 5π/4 radians

when x = π/4
y = e^-π/4 sin π/4 = .3224

when x = 5Ï€/4
y = e^-5Ï€/4 sin 5Ï€/4 = -.011139

Looking at your domain, I think you made a typo, and I will assume you meant
-π < x < π
so the second point above lies outside the domain,
but there is another solution of
x = -135° or -3π/4

if x = -3Ï€/4
y = e^-3Ï€/4 sin 3Ï€/4 = -.067

Within your domain, the stationary points are
(Ï€/4, .3224) and (-3Ï€/4, -.067)

Explain Bot Explain Bot answered
7 months ago

To find the coordinates of the stationary points, we need to set the derivative of the function to zero and solve for x.

In this case, we have the derivative dy/dx = e^(-x)(cos(x) - sin(x)).

Setting this derivative equal to zero, we get:

e^(-x)(cos(x) - sin(x)) = 0

Since e^(-x) is never equal to zero, we can simplify the equation to:

cos(x) - sin(x) = 0

Next, we need to solve this equation for values of x that satisfy it.

To do this, we can transform the equation cos(x) - sin(x) = 0 into an equation involving tan(x). Recall that tan(x) = sin(x) / cos(x).

Rearranging the equation, we have sin(x) = cos(x). Dividing both sides by cos(x), we get:

tan(x) = 1

So, at stationary points, tan(x) = 1.

Now, to determine the coordinates of the stationary points, we need to find the values of x that satisfy tan(x) = 1 within the given interval (π < x < π).

To solve this equation, we can use the inverse function of tan, which is arctan:

x = arctan(1)

Using a calculator or trigonometric tables, we find that arctan(1) = π/4.

Therefore, the value of x at the stationary point is π/4.

Now, to find the y-coordinate at this point, we substitute the value of x back into the original function y = e^(-x)sin(x):

y = e^(-Ï€/4) * sin(Ï€/4)

Again, you can use a calculator to find the approximate value.

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