Yeah that is totally right!!!!
:D
A shopper in a supermarket pushes a cart with a force of 35 N directed at an angle of 52(angle sign here) downward from the horizontal. Find the work done by the shopper on the cart as the shopper moves along a 50.0 m length of aisle.
Someone tell me if this is right:
W= (35.0N) (50.0m)(cos25.0)
W= 1586 J
If not please show me how to do it.
:D
The work done on an object is given by the equation:
W = F * d * cos(theta)
Where:
W is the work done on the object,
F is the force applied on the object,
d is the distance the object is moved, and
theta is the angle between the force and the direction of motion.
In this case:
F = 35.0 N (the force applied by the shopper),
d = 50.0 m (the distance the shopper moves), and
theta = 52° (the angle between the force and the horizontal direction).
Now, plug the values into the formula:
W = (35.0 N) * (50.0 m) * cos(52°)
To evaluate this, you need to convert degrees to radians. The cosine function in most calculators assumes input in radians, so you need to use the conversion formula: radians = degrees * (Ï€/180).
Using the conversion formula, the angle in radians is:
theta_radians = 52° * (π/180) ≈ 0.907 radians
Now you can substitute the angle in radians into the equation:
W = (35.0 N) * (50.0 m) * cos(0.907 radians)
Evaluating the cosine function, you get:
W ≈ (35.0 N) * (50.0 m) * 0.623
Calculating this expression, you get:
W ≈ 1087.25 J
Therefore, the correct answer is approximately 1087.25 Joules.
Based on your calculation, it seems that you made a mistake in the calculation of the cosine. You used cos(25°) instead of cos(52°). By correcting that, you should find the correct answer of approximately 1087.25 J.