n+ (n-2)+(n-4)=30
solve for n, the bottom row.
solve for n, the bottom row.
second row:10
third row:12
Let's assume the number of cans in the third row (top row) is n.
According to the given information, each of the top two rows has 2 fewer cans than the row beneath it.
So, the second row has (n + 2) cans, since it has 2 fewer cans than the third row.
Similarly, the first row has (n + 4) cans, since it has 2 fewer cans than the second row.
Given that there are 30 cans altogether, we can write the equation:
(n + 4) + (n + 2) + n = 30
Simplifying the equation:
3n + 6 = 30
Subtracting 6 from both sides:
3n = 24
Dividing both sides by 3:
n = 8
So, there are 8 cans in the third row (top row).
The second row has (8 + 2) = 10 cans.
The first row has (10 + 2) = 12 cans.
Therefore, there are 12 cans in the first row, 10 cans in the second row, and 8 cans in the third row.
Let's assume the number of cans in the bottom row is "x".
According to the given information, the top two rows have 2 fewer cans than the row beneath them. So, the number of cans in the middle row would be "x - 2", and in the top row, it would be "x - 2 - 2" or "x - 4".
The total number of cans is given as 30. So, we can write the equation:
x + (x - 2) + (x - 4) = 30
Now, let's solve this equation to find the value of "x" which represents the number of cans in the bottom row:
3x - 6 = 30 (Combine like terms)
3x = 36 (Add 6 to both sides)
x = 12 (Divide both sides by 3)
Therefore, there are 12 cans in the bottom row. In the middle row, there would be 12 - 2 = 10 cans, and in the top row, there would be 10 - 2 = 8 cans.