Question

Can someone help me find the y and x intercept, or tell me how to do it please.

f(x)=x^2-5x+4

Answer 1

Set x = 0 and solve for the y intercepts. "y" and f(x) mean the same thing.

Then set f(x)= y = 0 and solve for the x intercepts. There is only one y-intercept, at f(x) = y = +4.

Answer 2

Thank you.

Please tell me if this is correct.

x=4
y=-5

Answer 3

That is neither the x-intercept nor the y-intercept.

I already told you that the y intercept is at x=0, y=4.

The x intercepts are at x = (4,0) and at (1,0)

Answer 4

y=3x+3 and y=-2x+3

Answer 5

Please use "Post a New Question" for new questions.

If you are trying to solve two simultaneous equations in two unknowns, subtract the second equation from the first, in this case.

That will leave you with 5x = 0, so x = 0. Use either of the original equations for y.

Answer 6

[AI-generated answer — Explain Bot]

Sure! Finding the y-intercept and x-intercepts of a function can help provide insights into the behavior and shape of a graph. To find the y-intercept, you need to set x equal to zero and solve for the corresponding value of y. To find the x-intercepts, you need to set y equal to zero and solve for the corresponding values of x.

Let's start by finding the y-intercept of the function f(x) = x^2 - 5x + 4. To find the y-intercept, we set x equal to zero:
f(0) = (0)^2 - 5(0) + 4
f(0) = 4
So the y-intercept is (0, 4).

Next, let's find the x-intercepts of the function. To do this, we set y (or f(x)) equal to zero and solve for x:
0 = x^2 - 5x + 4
To solve this quadratic equation, you can either factor it or use the quadratic formula:
Factoring:
0 = (x - 1)(x - 4)
By setting each factor equal to zero, we find:
x - 1 = 0 -> x = 1
x - 4 = 0 -> x = 4
So the x-intercepts are (1, 0) and (4, 0).

Therefore, the y-intercept is (0, 4) and the x-intercepts are (1, 0) and (4, 0).