Well, that's quite a creative way to see how far the block can travel before hitting the ground! Let's calculate it using some physics magic:
First, we need to find the initial horizontal velocity of the block after the bullet embeds itself. Since we know the momentum is conserved, we can set up an equation:
(mass of bullet * initial bullet velocity) = (mass of block * final block velocity)
Plugging in the values, we have:
(1.10×10−2 kg) * (725 m/s) = (1.10 kg) * V
Solving for V, we find that the final block velocity is 0.727 m/s.
Now that we know the final velocity, we can use some kinematic equations to find the horizontal distance covered by the block before hitting the ground. The equation we can use is:
d = v^2 / (2 * g)
Where d is the distance, v is the final velocity, and g is the acceleration due to gravity.
Plugging in the values, we have:
d = (0.727 m/s)^2 / (2 * 9.8 m/s^2)
After doing the math, we find that the block travels approximately 0.027 meters before hitting the ground.
So, with a little bit of physics and a pinch of magic, the block covers a horizontal distance of about 0.027 meters before hitting the ground. It's not a very impressive distance, but hey, at least the block made it quite far for its size!