I assume all three are in parallel
first combine the two 20 ohms
1/R = 1/20 + 1/20 = 1/10
Req = 10
now combine that 10 with the other 10
1/R = 1/10+1/10 = 2/10 = 1/5
so R = 5 Ohms in the end
first combine the two 20 ohms
1/R = 1/20 + 1/20 = 1/10
Req = 10
now combine that 10 with the other 10
1/R = 1/10+1/10 = 2/10 = 1/5
so R = 5 Ohms in the end
So, let's do the math. The reciprocal of 20 ohms is 1/20, and the reciprocal of 10 ohms is 1/10. Now, if we add these two fractions together, we get 3/20. Finally, let's take the reciprocal of 3/20, which is 20/3 or approximately 6.67 ohms.
Therefore, the circuit's total resistance is about 6.67 ohms. And voila, the resistance treasure is found – in a fun and ohm-azing way!
1/R_total = 1/R1 + 1/R2 + 1/R3 + ...
In this case, we have three resistors connected in parallel with resistances of 20 ohms, 20 ohms, and 10 ohms.
Using the formula, we can calculate the total resistance:
1/R_total = 1/20 + 1/20 + 1/10
1/R_total = 1/20 + 1/20 + 2/20
1/R_total = 4/20
1/R_total = 1/5
To find the total resistance, we take the reciprocal of both sides:
R_total = 5 ohms
Therefore, the total resistance of the parallel circuit is 5 ohms.
1/RTotal = 1/R1 + 1/R2 + 1/R3 + ...
In this case, you have three resistances in parallel: two resistors rated at 20 ohms and one resistor rated at 10 ohms. So, plugging in the values, the formula becomes:
1/RTotal = 1/20 + 1/20 + 1/10
To simplify this, you need to find a common denominator:
1/RTotal = 1/20 + 1/20 + 2/20
Now, add the fractions together:
1/RTotal = (1 + 1 + 2) / 20
1/RTotal = 4 / 20
1/RTotal = 1 / 5
Finally, invert both sides of the equation to find the total resistance:
RTotal = 5 ohms
Therefore, the total resistance of the parallel circuit is 5 ohms.