Question

What is the volume in liters of 15.0kg of CO2 at STP

Answer 1

Use PV = nRT. Don't forget to use T in Kelvin. Convert 15.0 kg to moles. moles = 15,000 g/molar mass. Substitute that for n.

Answer 2

i dont know cuz i dumb

Answer 3

[AI-generated answer — Step-by-Step Bot]

To find the volume of 15.0 kg of CO2 at STP (Standard Temperature and Pressure), we need to use the ideal gas law equation:

PV = nRT

where:
P = pressure (STP is defined as 1 atm)
V = volume (what we're trying to find)
n = number of moles of the gas
R = ideal gas constant (0.0821 L·atm/K·mol)
T = temperature in Kelvin (STP is defined as 273.15 K)

First, let's convert the mass of CO2 from kilograms to moles using its molar mass. The molar mass of CO2 is 44.01 g/mol.

mass of CO2 = 15.0 kg = 15,000 g
moles of CO2 = mass of CO2 / molar mass of CO2

moles of CO2 = 15,000 g / 44.01 g/mol

Next, we can substitute the values into the ideal gas law equation:

PV = nRT

(1 atm) * V = (moles of CO2) * (0.0821 L·atm/K·mol) * (273.15 K)

V = (moles of CO2) * (0.0821 L·atm/K·mol) * (273.15 K) / (1 atm)

Now, let's calculate the volume.

V = (15,000 g / 44.01 g/mol) * (0.0821 L·atm/K·mol) * (273.15 K) / (1 atm)

V ≈ 22,391.97 liters

Therefore, the volume of 15.0 kg of CO2 at STP is approximately 22,391.97 liters.

Answer 4

[AI-generated answer — Explain Bot]

To find the volume of a gas at Standard Temperature and Pressure (STP), you can use the ideal gas law. The ideal gas law is expressed as:

PV = nRT

Where:
P = pressure (in atmospheres)
V = volume (in liters)
n = number of moles of gas
R = gas constant (0.0821 L·atm/(mol·K))
T = temperature (in Kelvin)

At STP, the pressure is 1 atm and the temperature is 273 K.

Given the mass of CO2 (15.0 kg), we need to find the number of moles of CO2 using its molar mass. The molar mass of CO2 is 44.01 g/mol.

First, we convert the mass from kg to grams:
15.0 kg * 1000 g/kg = 15000 g

Next, we calculate the number of moles:
n = mass / molar mass
n = 15000 g / 44.01 g/mol ≈ 340.83 mol

Now, we can substitute the values into the ideal gas law equation, along with the known values for STP:

P * V = n * R * T

Since we know that P = 1 atm, R = 0.0821 L·atm/(mol·K), and T = 273 K, we can rearrange the equation to solve for V:

V = (n * R * T) / P
V = (340.83 mol * 0.0821 L·atm/(mol·K) * 273 K) / 1 atm

Evaluating the expression gives:
V ≈ 7707.16 L

Therefore, the volume of 15.0 kg of CO2 at STP is approximately 7707.16 liters.