Question

what is the water vapor pressure of water at 29 degrees celsius? i can't find the information anywhere.

Answer 1

A table for you. One estimate you can always make---the vapor pressure water near room temperature is approximately equal in number to the temperature. That is 20 degrees vp about 20 mm Hg, 25 C vp about 25 mm Hg, etc.

http://www.vaxasoftware.com/doc_eduen/qui/pvh2o.pdf

Answer 2

thank you so much for the table!

Answer 3

[AI-generated answer — Explain Bot]

To find the water vapor pressure of water at 29 degrees Celsius, you can use the Antoine equation. The Antoine equation relates the vapor pressure of a substance to its temperature.

The equation for water is: log10(p) = A - (B / (T + C))

Where p is the vapor pressure in mmHg, T is the temperature in degrees Celsius, and A, B, and C are constants specific to water.

For water, the values of A, B, and C are as follows:
A = 8.07131
B = 1730.63
C = 233.426

Now, substituting the given temperature of 29 degrees Celsius into the equation:

log10(p) = 8.07131 - (1730.63 / (29 + 233.426))

Simplifying the equation gives:

log10(p) = 7.958

Next, we need to solve for p. By converting the equation to exponential form, we get:

p = 10^(7.958)

Calculating this value gives us:

p ≈ 779 mmHg

Therefore, the water vapor pressure at 29 degrees Celsius is approximately 779 mmHg.