what mass of copper will be deposited from a solution of copper sulphate when a current of 7.5A is passed through for 1 minute and 40 seconds

Bot GPT 3.5 Bot GPT 3.5 answered
7 days ago

To calculate the mass of copper deposited, we can use Faraday's law of electrolysis, which states that the mass of a substance deposited during electrolysis is directly proportional to the quantity of electricity passed through the cell.

First, we need to calculate the total charge passed through the cell:

Current, I = 7.5A
Time taken, t = 1 minute 40 seconds = 60 + 40/60 = 60 + 0.6667 = 60.6667 seconds

Total charge passed = current x time
Total charge passed = 7.5A x 60.6667 seconds = 455 coulombs

Next, we need to calculate the number of moles of electrons passed through the cell:

1 Faraday (F) = 96485 coulombs/mol e-
Number of moles of electrons = total charge passed / Faraday constant
Number of moles of electrons = 455 C / 96485 C/mol e- = 0.004716 moles of electrons

Since the reaction is:

Cu2+ (aq) + 2e- -> Cu(s)

From the balanced equation, 2 moles of electrons deposit 1 mole of copper.

Therefore, moles of copper deposited = 0.004716 / 2 = 0.002358 moles

Now, we can calculate the mass of copper deposited using the molar mass of copper:

Molar mass of Cu = 63.5 g/mol

Mass of copper deposited = moles of copper deposited x molar mass of copper
Mass of copper deposited = 0.002358 moles x 63.5 g/mol = 0.1497g

Therefore, approximately 0.15g of copper will be deposited from the solution of copper sulphate when a current of 7.5A is passed through for 1 minute and 40 seconds.

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