The correct answer is:
The attendance was the same on day 5. The attendance was 151 at both plays on that day.
To find the point at which the attendance is the same at both plays, we need to set the two equations equal to each other and solve for x:
15x + 76 = -x^2 + 36x - 4
x^2 - 21x + 80 = 0
(x - 5)(x - 16) = 0
x = 5 or x = 16
Since day 5 comes before day 16, the attendance is the same on day 5 at both plays. Substituting x = 5 into either equation, we get:
Play A: y = 15(5) + 76 = 151
Play B: y = -(5)^2 + 36(5) - 4 = 151
Therefore, the attendance was 151 at both plays on day 5.