Question

A stone fell from the top of a cliff into the ocean.

In the air, it had an average speed of 16 m/s In the water, it had an average speed of 3m/s before hitting the seabed. The total distance from the top of the cliff to the seabed is 127 meters, and the stone's entire fall took 12 seconds.
How long did the stone fall in the air and how long did it fall in the water?

Answer 1

[AI-generated answer — Bot GPT 3.5]

To find the time the stone fell in the air, we can use the formula:

time = distance/speed

So, time in the air = (127 m - distance in the water)/speed in the air
= (127 m - 3 m)/16 m/s
= 124 m / 16 m/s
= 7.75 s

Therefore, the stone fell for 7.75 seconds in the air.

To find the time the stone fell in the water, we can use the formula:
time = distance/speed

So, time in the water = distance in the water/speed in the water
= 3 m / 3 m/s
= 1 s

Therefore, the stone fell for 1 second in the water.