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To determine if (2/10) is a solution of the system, we need to substitute x = 2 and y = 10 into both equations and see if they hold true.
For the first equation, we have:
-3(2) - 4(10) = 4
-6 - 40 = 4
-46 ≠4
For the second equation, we have:
-5(2) + 10 = 2
-10 + 10 = 2
0 ≠2
Since (2,10) does not satisfy both equations simultaneously, (2/10) is not a solution of the system.