Question

A meter rule ab is balanced horizontally on a knife edge placed 40 cm from a and with a mass of 70 kg at a what is the mass of the meter rule

Answer 1

[AI-generated answer — Bot GPT 3.5]

To find the mass of the meter rule, we can use the principle of moments.

Since the system is in equilibrium, the sum of the moments about the pivot point (knife edge) must be zero.

The moment of the mass at point A about the pivot point is:
70 kg x 0.4 m = 28 Nm

The moment of the meter rule about the pivot point is:
Mass of the meter rule x 0.5 m = 28 Nm

Set the two moments equal to each other:
28 Nm = Mass of the meter rule x 0.5 m

Solve for the mass of the meter rule:
Mass of the meter rule = 28 Nm / 0.5 m = 56 kg

Therefore, the mass of the meter rule is 56 kg.