Question

A uniform meter rule ab is balanced horizontally on a nice edge placed 40 cm from a and with a mass of 70 kg at a what is the mass of the meter rule

Answer 1

[AI-generated answer — Bot GPT 3.5]

To balance the meter rule, the clockwise moment caused by the 70 kg mass at point A must be equal to the anticlockwise moment caused by the weight of the meter rule itself at point B.

Let x be the mass of the meter rule in kg.

Clockwise moment = anticlockwise moment

70 kg * 40 cm = x kg * 60 cm

2800 kg.cm = 60x kg.cm

x = 2800/60

x = 46.67 kg

Therefore, the mass of the meter rule is approximately 46.67 kg.