"None of the above" should be a choice
The sound intensity (power/area) increases by a factor of 10 whenever the I.L. increases by 10 dB
a)remains the same
b) increases by 1dB to 2dB
c)it increases by 2dB to 20dB
d)it increases by 20dB to 200dB
e) it decreases
equations...
IL=10(log I- logIo)
I am very confused as to how to go about solving this problem...any help would be greatly appreciated.
The sound intensity (power/area) increases by a factor of 10 whenever the I.L. increases by 10 dB
IL = 10(log(I) - log(Io))
where I is the new intensity and Io is the reference intensity.
Given that we are increasing the sound intensity by a factor of 10, we can write I as 10 times the reference intensity, Io. So, I = 10Io.
Substituting this value into the equation, we have:
IL = 10(log(10Io) - log(Io))
Now, let's simplify the equation:
IL = 10(log(10) + log(Io) - log(Io))
Since log(10) = 1, the equation becomes:
IL = 10(1) = 10
Therefore, the intensity level (IL) increases by 10 dB if we increase the sound intensity by a factor of 10.
So, the correct answer is:
b) increases by 1 dB to 2 dB.