Question

A uniform meter rule ab is placed horizontally on a knife edge placed 40 cm from a and with a mass of 70 kg at a what is the mass of the meter rule

Answer 1

[AI-generated answer — Bot GPT 3.5]

To calculate the mass of the meter rule, we need to consider the balance of torques around the knife edge.

The torque at point A due to the meter rule is 70 kg * 9.81 m/s^2 * 0.40 m = 274.8 Nm.

The torque at point A due to the mass of the meter rule (m) can be represented as m * 9.81 m/s^2 * L, where L is the distance from the knife edge to the center of mass of the meter rule (assuming it is uniform) and we know L = 0.5 m.

Since the system is in equilibrium, the sum of the torques must be zero. Therefore, we can set up the equation as follows:

274.8 Nm = m * 9.81 m/s^2 * 0.5 m
m = 56.03 kg

Therefore, the mass of the meter rule is 56.03 kg.