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Since segment CB is tangent to the circle, we know that it is perpendicular to radius CD at the point of tangency. This forms a right triangle with CB as the hypotenuse, and CD as one of the legs.
We can use the Pythagorean theorem to solve for the length of CD:
CD^2 + 6^2 = 7^2
CD^2 + 36 = 49
CD^2 = 13
CD = sqrt(13)
Therefore, the length of segment CD is sqrt(13).