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To rationalize the denominator, we multiply the numerator and denominator by the cube root of 6:
\frac{\sqrt[3]{2}}{\sqrt[3]{6}} = \frac{\sqrt[3]{2} \cdot \sqrt[3]{6}}{\sqrt[3]{6} \cdot \sqrt[3]{6}}
Simplifying the expression:
\frac{\sqrt[3]{2} \cdot \sqrt[3]{6}}{\sqrt[3]{6} \cdot \sqrt[3]{6}} = \frac{\sqrt[3]{12}}{6}
Therefore, the expression with a rationalized denominator is \frac{\sqrt[3]{12}}{6}