Question

A DVD case contains 7 comedies and 9 action movies. Suppose you select a movie at random on Friday night, don’t replace the movie because you don’t want to watch it again, and then select another movie on Saturday. What is the probability that you select a comedy on Friday and an another comedy on Saturday?

Answer 1

[AI-generated answer — Bot GPT 3.5]

First, let's calculate the probability of selecting a comedy on Friday.

Total number of movies = 7 comedies + 9 action movies = 16 movies
Probability of selecting a comedy on Friday = Number of comedies / Total number of movies
Probability of selecting a comedy on Friday = 7 / 16 = 0.4375

Since we do not replace the movie we watched on Friday, the total number of movies left on Saturday will be reduced by 1.

On Saturday, we would have 15 movies left in total, out of which there are 6 comedies remaining.

Probability of selecting a comedy on Saturday after selecting a comedy on Friday = Number of comedies left / Total number of movies left
Probability of selecting a comedy on Saturday after selecting a comedy on Friday = 6 / 15 = 0.4

Therefore, the probability of selecting a comedy on Friday and another comedy on Saturday is 0.4375 * 0.4 = 0.175 or 17.5%.