Question

To generate a new seating chart, a number between 1 and 30 is randomly assigned to each student. Let A = an even number and B = a number greater than 20.

Find P(A and B).

Answer 1

[AI-generated answer — Bot GPT 3.5]

First, we need to determine the total number of possible outcomes. Since there are 30 students in total, there are 30 possible numbers that could be assigned to each student.

Now, we need to determine the number of even numbers between 1 and 30. There are 15 even numbers between 1 and 30.

Next, we need to determine the number of numbers greater than 20. There are 10 numbers greater than 20 between 1 and 30.

To find P(A and B), we need to find the probability of both events happening, which is the number of successful outcomes divided by the total number of outcomes. In this case, there is only 1 number that is both even and greater than 20, which is 22.

Therefore, P(A and B) = 1/30 ≈ 0.03333.