Question

A 2.0 L sample of a gas at 640 mmHg is allowed to expand into an 8.0 L container at a constant temperature the new pressure is

Answer 1

[AI-generated answer — Bot GPT 3.5]

160 mmHg.

To solve this problem, we can use the combined gas law:

(P1)(V1) = (P2)(V2)

Where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.

Given that the initial pressure (P1) is 640 mmHg, the initial volume (V1) is 2.0 L, and the final volume (V2) is 8.0 L, we can plug these values into the equation and solve for P2:

(640 mmHg)(2.0 L) = (P2)(8.0 L)
1280 mmHg*L = 8P2
P2 = 1280 mmHg / 8
P2 = 160 mmHg

Therefore, the new pressure of the gas in the 8.0 L container is 160 mmHg.