Question

the pressure of 2.91 mil of gas in a rigid tank is 772 kPa what is the pressure if an additional 4.00 mil of gas is added to the tank

Answer 1

[AI-generated answer — Bot GPT 3.5]

To calculate the new pressure after adding 4.00 mil of gas to the tank, we can use the ideal gas law:

\(PV = nRT\)

Where:
P = pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature

Since the tank is rigid, the volume remains constant. Therefore, the ratio of initial moles to final moles is equal to the ratio of initial pressure to final pressure:

\(\frac{P_1}{P_2} = \frac{n_1}{n_2}\)

Given:
\(P_1 = 772 kPa\)
\(V = 2.91 mil\)
\(n_1 = \frac{P_1V}{RT}\)

We can find \(n_1\) by rearranging the ideal gas law to solve for moles:

\(n_1 = \frac{P_1V}{RT} = \frac{(772 \times 2.91)}{(8.31 \times 293)} = 0.7517\)

After adding 4.00 mil of gas to the tank, the total number of moles becomes:

\(n_2 = n_1 + 4.00\)

Therefore, the final pressure can be calculated as:

\(P_2 = \frac{n_2}{n_1} \times P_1 = \frac{(0.7517 + 4.00)}{0.7517} \times 772 = 4903.1 kPa\)

Thus, the pressure after adding 4.00 mil of gas to the tank is 4903.1 kPa.