Question

a steel canister holds 50.0 L of helium gas at 32.0 C and 117 kPa the gas is cooled until the pressure watches 14.2 kPa what is the kelvin temperature of the helium

Answer 1

[AI-generated answer — Bot GPT 3.5]

To solve this problem, we can use the combined gas law:

(P1V1) / T1 = (P2V2) / T2

Where:
P1 = 117 kPa
V1 = 50.0 L
T1 = 32.0°C + 273.15 = 305.15 K
P2 = 14.2 kPa
V2 = 50.0 L
T2 = unknown

Now, we can plug in the values and solve for T2:

(117 kPa * 50.0 L) / 305.15 K = (14.2 kPa * 50.0 L) / T2

5850 / 305.15 = 710 / T2
T2 = (710 * 305.15) / 5850
T2 = 37.04 K

Therefore, the Kelvin temperature of the helium gas after it is cooled to 14.2 kPa pressure is approximately 37.04 K.