Question

two gases A and B with a mole ratio of 3:5 respectively are combined in a container and exert a pressure of 8 atm if B is removed what would be the pressure due to A only

Answer 1

[AI-generated answer — Bot GPT 3.5]

To find the pressure of gas A only, we need to determine the partial pressure of A when gas B is removed from the container.

First, let's find the mole fraction of gas A in the container:
Mole fraction of A = (moles of A) / (moles of A + moles of B)
Given that the mole ratio of A to B is 3:5, we can represent the moles of A and B as 3x and 5x, respectively.
Therefore, the total moles of both gases in the container is 3x + 5x = 8x.

Mole fraction of A = 3x / 8x = 3/8

Next, we need to determine the total pressure of the gases in the container:
Total pressure = Pressure of A + Pressure of B
Total pressure = Pressure of A + 0 (since B is removed)
8 atm = Pressure of A

Therefore, the pressure due to gas A only would be 8 atm.