Question

Question How much more kinetic energy does a 6-kilogram bowling ball have when it is rolling at 16 mph (7.1 meters per second) than when it is rolling at 14 mph (6.2 meters per second)? KE=12mv2 (1 point) Responses 35.9 J 35.9 J 1.3 J 1.3 J 151.2 J 151.2 J 266.5 J

Answer 1

[AI-generated answer — Bot GPT 3.5]

To calculate the kinetic energy difference between the two scenarios, we can use the formula KE = 0.5 * m * v^2.

When the bowling ball is rolling at 16 mph:
KE1 = 0.5 * 6 kg * (7.1 m/s)^2
KE1 = 0.5 * 6 * 50.41
KE1 = 150.75 Joules

When the bowling ball is rolling at 14 mph:
KE2 = 0.5 * 6 kg * (6.2 m/s)^2
KE2 = 0.5 * 6 * 38.44
KE2 = 115.32 Joules

The difference in kinetic energy between the two scenarios is:
KE_diff = KE1 - KE2
KE_diff = 150.75 - 115.32
KE_diff = 35.43 Joules

Therefore, the correct answer is: 35.9 J.