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To solve this system of equations, we can use the method of substitution or elimination.
Let's start by using the elimination method to solve this system:
Multiply both sides of the second equation by 5 to make the coefficients of x the same in both equations:
5(x - 6y) = 5(22)
5x - 30y = 110
Now we have the two equations:
5x + 2y = 14
5x - 30y = 110
Subtract the first equation from the second equation:
5x - 30y - (5x + 2y) = 110 - 14
-32y = 96
y = -3
Now, substitute y = -3 into either of the original equations to solve for x:
5x + 2(-3) = 14
5x - 6 = 14
5x = 20
x = 4
So the solution to the system of equations is x = 4 and y = -3.