m=-5
The rate of change is -5 points per day for turning in the homework assignment late.
Responses
m=5
m equals 5
m=−5
m equals negative 5
m=−100
m equals negative 100
m=100
m equals 100
The rate of change is -5 points per day for turning in the homework assignment late.
x y
2.6 −6
3.2 3
Determine the rate of change of the linear function given as a table of values.
(1 point)
Responses
m=−5
m equals negative 5
m=−15
m equals negative 15
m=15
m equals 15
m=0.067
The rate of change of the linear function given by the table is 15.
Responses
b=15.71
b equals 15.71
b=11
b equals 11
b=12.29
b equals 12.29
b=−5
Given m = -47 and a point on the line (14,3), we can substitute these values into the equation:
3 = -47(14) + b
3 = -658 + b
b = 3 + 658
b = 661
Therefore, the initial value (y-intercept) of the linear function is b = 661.
None of the provided responses match the correct value.
b equals 15.71
b=11
b equals 11
b=12.29
b equals 12.29
b=−5
b = 15.71
Therefore, the initial value (y-intercept) of the linear function is b = 15.71.
(1 point)
Responses
The initial value is −23, and the rate of change is 23.
The initial value is negative Start Fraction 2 over 3 End Fraction , and the rate of change is Start Fraction 2 over 3 End Fraction .
The initial value is −2, and the rate of change is 23.
The initial value is negative 2 , and the rate of change is Start Fraction 2 over 3 End Fraction .
The initial value is 23, and the rate of change is −23.
The initial value is Start Fraction 2 over 3 End Fraction , and the rate of change is negative Start Fraction 2 over 3 End Fraction .
The initial value is 16, and the rate of change is 32.
The initial value is 16, and the rate of change is 32.
Therefore, the initial value and the rate of change of the linear function given in the graph would be 16 and 32 respectively.