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First, calculate the moles of NaOH used in the titration:
Volume of NaOH used = 33.87 mL - 0.55 mL = 33.32 mL = 0.03332 L
Moles of NaOH = Molarity x Volume(poured out) = 0.1524 mol/L x 0.03332 L = 0.00503 mol
Since the reaction is 1:1 between HCl and NaOH, the moles of HCl in the solution are also 0.00503 mol.
Next, calculate the molarity of the HCl solution:
Volume of HCl used = 50.00 mL = 0.05000 L
Molarity of HCl = Moles of HCl / Volume of HCl used = 0.00503 mol / 0.05000 L = 0.1006 M
Therefore, the molarity of the HCl solution is 0.1006 M.