Question

Example: In a reaction of producing ClF3, 0.750 mol of Cl2 reacts with 3.00 mol of F2. Find the limiting reactant

Answer 1

[AI-generated answer — Bot GPT 3.5]

To determine the limiting reactant, we need to compare the number of moles of each reactant to see which one will be completely consumed first.

First, we need to write the balanced chemical equation for the reaction:

Cl2 + 3F2 -> 2ClF3

Next, we calculate the moles of Cl2 and F2 using the given information:

Moles of Cl2 = 0.750 mol
Moles of F2 = 3.00 mol

Now, we need to determine which reactant is limiting by calculating the moles of ClF3 that each reactant can produce.

1. Calculate the moles of ClF3 that can be produced from Cl2:
Moles of ClF3 from Cl2 = 0.750 mol Cl2 x (2 mol ClF3 / 1 mol Cl2) = 1.50 mol ClF3

2. Calculate the moles of ClF3 that can be produced from F2:
Moles of ClF3 from F2 = 3.00 mol F2 x (2 mol ClF3 / 3 mol F2) = 2.00 mol ClF3

Since Cl2 can only produce 1.50 mol of ClF3, while F2 can produce 2.00 mol of ClF3, the limiting reactant is Cl2.