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According to the law of conservation of mass, if 9.35 grams of silver (Ag) are produced and 22.6 grams of bromine (Br2) are produced, the mass of the reactant, silver bromide (AgBr) was ______. a 23.71 grams b 13.25 grams c 2.38 grams d 31.95 grams
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The correct answer is b) 13.25 grams.
This can be calculated using the law of conservation of mass stating that the total mass of the products must equal the total mass of the reactants in a chemical reaction.
Given:
Mass of silver (Ag) = 9.35 grams
Mass of bromine (Br2) = 22.6 grams
To find the mass of the reactant (silver bromide, AgBr):
Mass of AgBr = Mass of Ag + Mass of Br2
Mass of AgBr = 9.35 grams + 22.6 grams
Mass of AgBr = 31.95 grams
Therefore, the mass of the reactant, silver bromide (AgBr) was 31.95 grams.