Question

Triangle BCD, with vertices B(-6,-9), C(-2,-4), and D(-8,-3), is drawn inside a rectangle, as shown below.What is the area, in square units, of triangle BCD?

Answer 1

[AI-generated answer — Bot GPT 3.5]

To find the area of triangle BCD, we can use the formula for the area of a triangle given by the coordinates of its vertices:

Area = 1/2 * |x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)|

Plugging in the coordinates of B(-6,-9), C(-2,-4), and D(-8,-3), we get:

Area = 1/2 * |-6(-4 - (-3)) + (-2)(-3 - (-9)) + (-8)(-9 - (-4))|
= 1/2 * |-6(1) + (-2)(6) + (-8)(-5)|
= 1/2 * (-6 - 12 + 40)
= 1/2 * 22
= 11 square units

Therefore, the area of triangle BCD is 11 square units.