Part 1:
Using the ideal gas law, we can calculate the new volume of gas at 14.6 atm:
V1 = 4.5 L (initial volume)
P1 = 4.0 atm (initial pressure)
P2 = 14.6 atm (final pressure)
V2 = V1 * P1 / P2
V2 = 4.5 L * 4.0 atm / 14.6 atm
V2 = 1.23 L
Therefore, the volume of gas at 14.6 atm is 1.23 L.
Part 2:
Converting 230. mmHg to atm:
1 atm = 760 mmHg
230. mmHg = 230. mmHg / 760 mmHg/atm = 0.303 atm
Using the ideal gas law:
V1 = 4.5 L (initial volume)
P1 = 4.0 atm (initial pressure)
P2 = 0.303 atm (final pressure)
V2 = V1 * P1 / P2
V2 = 4.5 L * 4.0 atm / 0.303 atm
V2 = 59.406 L
Therefore, the volume of gas at 230. mmHg is 59.406 L.